Part 12 of 12 · Smith Chart & Impedance Matching Series overview →

This article builds on Part 11: Single-Stub and Double-Stub Impedance Matching. This is the final article of the series.

Smith chart trace of a patch antenna measured from 2.04 to 2.76 GHz, forming a loop that passes near the centre, with the 2.4 GHz point marked and the part inside the minus 10 dB circle highlighted
A patch antenna swept from 2.04 to 2.76 GHz. The trace loops around near the centre at resonance; the highlighted section lies inside the −10 dB (VSWR 1.92) circle, and the 2.4 GHz marker sits right on its edge. Try it in the Smith Chart Calculator →

From Theory to the Bench

Over the previous eleven parts we built up impedance, characteristic impedance, Γ, VSWR, line transformation, the chart itself, and matching with lumped elements and stubs. In practice these ideas meet in a few recurring tasks:

  • Antenna matching — measure the antenna, then design a network that brings its band into the −10 dB circle.
  • Measurement — read a VNA's Smith chart display, recognise resonances, and remove cables and fixtures from the result.
  • Amplifier design — choose source and load impedances for gain, noise or stability, using circles drawn on the chart.
  • Filters, couplers and passive networks — check input and output match over the band and spot parasitic resonances.

All the examples below use the Smith Chart Calculator with its built-in sample antenna file, so you can reproduce every step.

Matching a Measured Antenna

A VNA saves its measurement as a Touchstone file: an .s1p file for a one-port device such as an antenna, listing frequency and S11 (as magnitude/angle, dB/angle or real/imaginary) at every point. Loading the file into the calculator plots the antenna's impedance at the chosen design frequency and lets the matching solver work on the measured data rather than on a single assumed impedance.

Smith chart with the measured patch antenna impedance at 2.4 GHz plotted just right of centre, slightly inductive, with the frequency trace dashed
At 2.4 GHz the sample patch antenna measures 92.0 + j13.6 Ω (z = 1.84 + j0.27): slightly above resonance on the high-resistance side. Try it in the Smith Chart Calculator →
S11 versus frequency for the patch antenna with a shallow dip reaching minus 11.6 dB near 2.42 GHz
S11 versus frequency: the dip reaches only −11.6 dB at 2.42 GHz. Try it in the Smith Chart Calculator →
Sweep readouts: S11 minus 10.19 dB at 2.4 GHz, VSWR 1.90, minus 10 dB band 2.398 to 2.442 GHz, 44.1 MHz, best match minus 11.64 dB at 2.42 GHz
The −10 dB band is only 44 MHz (1.8%), and 2.4 GHz sits right at its lower edge. Try it in the Smith Chart Calculator →

The diagnosis from the chart is immediate: the resonance loop crosses the real axis well to the right of the centre, near z ≈ 1.8 (about 90 Ω), so the antenna's resistance at resonance is too high; and the feed inductance pushes the best match up to 2.42 GHz. Two kinds of fix are possible:

  • Change the antenna — move the feed point toward the patch centre to lower the resistance, or lengthen the patch slightly to lower the resonance. On the chart, the loop shrinks toward the centre and rotates so 2.4 GHz lands in the middle of the highlighted section.
  • Add a matching network — keep the antenna and transform 92 + j13.6 Ω to 50 Ω at 2.4 GHz. The matching solver finds the options:
Matching solver results for the measured antenna listing two L-networks, two pi-networks and two T-networks, all with minus 10 dB bands from 2.37 to 2.43 GHz
Solver output using the measured file. Because the load is inside the r = 1 circle (R > 50 Ω), only shunt-at-load L-networks exist. All networks give a −10 dB band of about 2.37–2.43 GHz: the antenna's own Q, not the network, now limits the bandwidth. Try it in the Smith Chart Calculator →
💡 The antenna sets the bandwidth

In Part 10 the load was held constant and an L-network achieved up to 105% bandwidth. With a real antenna whose impedance changes rapidly with frequency, every network gives roughly the same 60 MHz band. Matching can centre the band and deepen the null, but it cannot make a high-Q antenna broadband — that requires changing the antenna itself (thicker substrate, different geometry).

Reading Frequency Sweeps on the Chart

On a VNA, S11 is displayed as a trace rather than a point. A few patterns recur:

Trace shapeMeaning
Clockwise motion with increasing frequencyNormal for any passive device (Foster's reactance theorem); counter-clockwise segments indicate measurement error or active circuits
A loop or "kink"A resonance — antenna, filter pole or parasitic. The tighter the loop, the higher the Q
Loop crossing the real axis right of centreResistance at resonance > Z₀ (crossing left of centre: < Z₀)
Loop passing through the centreA perfect match at that frequency — the target when tuning a resonant antenna
Loop shifted up (inductive) or down (capacitive)A series reactance such as feed-pin inductance; the best match moves away from the real-axis crossing
Fast spiral around the chartA long cable or fixture between the calibration plane and the device
Trace near the outer edgeNearly pure reactance — off-resonance antenna, or a lossless network

In the hero figure the loop crosses the real axis at about 90 Ω and is lifted slightly into the inductive half by the probe's feed inductance. Moving an inset feed or probe toward the patch centre lowers the resistance at resonance until the loop passes through the centre.

How Cable Loss Hides a Bad Match

On a lossless line the impedance moves around a constant-VSWR circle (Part 5). A real cable with one-way loss A dB attenuates the reflected wave twice, so the point spirals inward toward the centre as the cable gets longer:

Reflection coefficient seen through a lossy line
|Γin|=|ΓL|×10−2A/20 RLin=RLL+2A
Measured at the transmitter, the return loss looks better by twice the cable loss. A long enough cable makes any load — even a short — look matched.
Fig 1 — The load 25 + j50 Ω seen through 0.75 λ of cable with 3 dB total one-way loss. Instead of staying on the VSWR 4.27 circle, the point spirals inward to the −10 dB circle.
00.20.5125+j0.2−j0.2+j0.5−j0.5+j1−j1+j2−j2+j5−j5∞antenna: |Γ| = 0.62at radio: |Γ| = 0.31
lossless VSWR circle−10 dB circle
Cable loss (one way)|Γ| at the radioApparent return lossApparent VSWR
0 dB (at the antenna)0.6204.15 dB4.27
1 dB0.4936.15 dB2.94
2 dB0.3918.15 dB2.29
3 dB0.31110.15 dB1.90
⚠️ Measure at the antenna

A VSWR meter at the bottom of a mast reading 1.9 : 1 through 3 dB of cable is hiding an antenna at 4.3 : 1 — and the station is also losing half its power in the cable. Always calibrate at, or de-embed to, the antenna terminals.

Removing Cables and Fixtures: Port Extension

A VNA is calibrated at its connector, but the device often sits at the end of a test cable or PCB trace. The extra length rotates the measurement clockwise (and, if lossy, spirals it inward). Port extension undoes this mathematically: the analyser rotates the data counter-clockwise by 720° × ℓ/λ at every frequency (and optionally removes loss). On the chart, a correctly set port extension makes an open-circuit fixture collapse to the single open point at the right edge, instead of smearing around the outer circle.

For more complex fixtures — connectors, launches, discontinuities — full de-embedding uses the fixture's own S-parameters. The principle is the same: move the reference plane to the device, so the chart shows the device, not the test setup.

Smith Chart Circles in Amplifier Design

A transistor's performance depends on the source impedance it sees (Γ_S) and the load impedance (Γ_L). Amplifier design software plots several families of circles on the Smith chart to show the trade-offs:

CirclePlotted onWhat it shows
Stability circlesΓ_S and Γ_L planesBoundary between source/load impedances that keep the device stable and those that can make it oscillate
Constant-gain circlesΓ_S or Γ_L planeImpedances giving the same available or operating gain; the smallest circle is the maximum-gain (conjugate-match) point
Noise-figure circlesΓ_S planeSource impedances giving the same noise figure, centred on Γ_opt
Load-pull contoursΓ_L planeMeasured output power and efficiency for power amplifiers

A low-noise amplifier designer typically chooses Γ_S on a low-noise circle that is also in the stable region and still gives acceptable gain, then designs an L-network or stub match (Parts 10 and 11) to present that Γ_S to the transistor. The chart makes the compromise between noise, gain and stability visible in one picture.

Practical Tips

  • Simulate with real parts. Use component S-parameter models — a 1 pF capacitor at 2.4 GHz may behave like 1.1 pF with 0.4 nH of series inductance.
  • Include pads and traces. A few millimetres of trace between components is a line section that rotates the impedance; add it to the ladder.
  • Prefer low-Q paths. Choose matching paths that stay close to the real axis; they are wider band and less sensitive to tolerances.
  • Leave a tuning footprint. A π-pad footprint (shunt–series–shunt) lets you build any L-network on the bench.
  • Check the whole band. A match at one frequency is not a match; sweep and confirm the trace stays inside the target circle.

Worked Examples

01

Reading the Antenna at 2.4 GHz

Problem: The antenna file gives Z = 92.0 + j13.6 Ω at 2.4 GHz. Find Γ, S11 and VSWR.

Γ=42.0+j13.6142.0+j13.6=0.309∠12.4° S11=−10.2 dB VSWR=1.90
Answer: Γ = 0.309 ∠ 12.4°, S11 = −10.2 dB, VSWR 1.90 — just inside specification
02

Designing the Antenna Match

Problem: Verify the low-pass L-network from the solver: shunt C = 0.766 pF at the antenna, series L = 3.111 nH toward the radio.

yL=11.84+j0.272=0.532−j0.079 →+j0.578 z=1.00−j0.938 →+j0.938 1
Answer: B = +11.55 mS (0.766 pF) then X = +46.9 Ω (3.111 nH) — a perfect match at 2.4 GHz

Because z_L lies inside the r = 1 circle, the shunt element has to be at the antenna — the forbidden-region rule of Part 10.

03

VSWR Through a Lossy Cable

Problem: An antenna with VSWR 4.27 (|Γ| = 0.620) is fed through cable with 3 dB loss. What VSWR does a meter at the radio show?

|Γin|=0.620×10−6/20=0.311 VSWR=1.3110.689=1.90
Answer: the meter reads 1.90 : 1 (RL 10.15 dB) for an antenna that is really 4.27 : 1
04

Port Extension by Hand

Problem: A VNA reads Γ = 0.620 ∠ −128.3° at the end of a 50 Ω fixture 0.2933 λ long. What is the device impedance?

θL=−128.3°+720°×0.2933=−128.3°+211.2°=82.9°
Answer: Γ_L = 0.620 ∠ 82.9° → Z_L = 25 + j50 Ω

This is exactly the reverse of the line rotation in the single-stub design of Part 11: the fixture moved the load to the g = 1 circle.

05

Diagnosing the Patch From Its Sweep

Problem: Stepping the frequency in the calculator shows the trace crossing the real axis at 2.407 GHz with Z ≈ 90 Ω, while the best match (−11.6 dB) is at 2.42 GHz with Z ≈ 75 − j22 Ω. What do these two points tell you?

Γcross=90−5090+50=0.286(−10.9 dB) Γbest=25−j22125−j22=0.262(−11.6 dB)
Answer: the resonant resistance (~90 Ω) is too high, and a series feed inductance offsets the loop

The best match is not on the real axis, so it is not where the patch resonates. Moving the feed toward the patch centre to bring the resonant resistance to about 50 Ω, and lengthening the patch slightly (≈ 1%) to centre the band, would put the loop through the chart centre at 2.4 GHz.

Series Summary

Over twelve articles we have followed one idea from first principles to the bench:

  • Parts 1–3: impedance, characteristic impedance and the reflection coefficient Γ = (z − 1)/(z + 1).
  • Parts 4–5: standing waves, VSWR, and the line as an impedance transformer — a rotation on the chart.
  • Parts 6–9: the Smith chart itself — its construction, normalisation, circles and scales, and plotting.
  • Parts 10–12: lumped and stub matching, and the chart as the everyday tool of antenna, measurement and amplifier work.

Return to the series overview to revisit any part, or continue with our transmission line series for a deeper look at the lines themselves.

Put It Into Practice

Use the NEXT ANTENNAS calculators to apply the ideas from this article to real designs.